What is the derivative of (x^3+2x^{37}) ?

The derivative of (x^3+2x^{37}) is 37(x^3+2x)^{36}(3x^2+2)

What is the first derivative of (x^3+2x^{37}) ?

The first derivative of (x^3+2x^{37}) is 37(x^3+2x)^{36}(3x^2+2)

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\frac{d}{d x} ((x^{3} + 2 x)^{37})

37 (x^{3} + 2 x)^{36} (3 x^{2} + 2)

Solution steps

\frac{d}{d x} ((x^{3} + 2 x)^{37})

Apply the chain rule:

37 (x^{3} + 2 x)^{36} \frac{d}{d x} (x^{3} + 2 x)

= 37 (x^{3} + 2 x)^{36} \frac{d}{d x} (x^{3} + 2 x)

\frac{d}{d x} (x^{3} + 2 x) = 3 x^{2} + 2

= 37 (x^{3} + 2 x)^{36} (3 x^{2} + 2)

\frac{\partial}{\partial y} (x^{3} y^{4} + x^{4} y^{3})

\frac{d}{d x} (- \frac{10 x}{( x ^{2} - 9 ) ^{2}})

sin (cos (x))

x \to 0 - lim (e^{\frac{9}{x}})

What is the derivative of (x^3+2x^{37}) ?
The derivative of (x^3+2x^{37}) is 37(x^3+2x)^{36}(3x^2+2)
What is the first derivative of (x^3+2x^{37}) ?
The first derivative of (x^3+2x^{37}) is 37(x^3+2x)^{36}(3x^2+2)