What is the derivative of 10sec^2(x) ?

The derivative of 10sec^2(x) is 20sec^2(x)tan(x)

What is the first derivative of 10sec^2(x) ?

The first derivative of 10sec^2(x) is 20sec^2(x)tan(x)

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\frac{d}{d x} (10 sec^{2} (x))

20 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (10 sec^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (sec^{2} (x))

Apply the chain rule:

2 sec (x) \frac{d}{d x} (sec (x))

= 2 sec (x) \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 10 \cdot 2 sec (x) sec (x) tan (x)

Simplify

10 \cdot 2 sec (x) sec (x) tan (x) : 20 sec^{2} (x) tan (x)

= 20 sec^{2} (x) tan (x)

\int_{0}^{1} 2 π y (y - y^{7}) d y

\int - 2 x^{5} d x

\frac{\partial}{\partial y} (x + 2 - y)

\int_{0}^{5} \frac{1}{x ^{\frac{12}{13}}} d x

x^{2} - 4, 0, - 4, 3

What is the derivative of 10sec^2(x) ?
The derivative of 10sec^2(x) is 20sec^2(x)tan(x)
What is the first derivative of 10sec^2(x) ?
The first derivative of 10sec^2(x) is 20sec^2(x)tan(x)