What is the limit as x approaches 2 of x^2-4x+4 ?

The limit as x approaches 2 of x^2-4x+4 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of x^2-4x+4

x \to 2 lim (x^{2} - 4 x + 4)

0

Solution steps

x \to 2 lim (x^{2} - 4 x + 4)

Plug in the value

x = 2

= 2^{2} - 4 \cdot 2 + 4

Simplify

= 0

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (1) = 0, y^{^{'}} (1) = 1

x \to 1 lim (- 1.6 x + 0.6)

\int \frac{1}{x ln ( 3 x )} d x

\frac{d}{d x} (\frac{ln ( x ) + 1}{ln ( x ) - 1})

x \to - 2 lim (\frac{2 - ∣ x ∣}{2 + x})

What is the limit as x approaches 2 of x^2-4x+4 ?
The limit as x approaches 2 of x^2-4x+4 is 0