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Popular >

y^'=2xy+xy^2

Solution

y^{^{'}} = 2 x y + x y^{2}

Solution

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

y^{'} (x) = 2 x y + x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

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x \to \infty lim (2 x^{5})

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x \to 0 + lim (x^{8} ln (x))

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy+xy^2 ?
The solution for y^'=2xy+xy^2 is y= 2/(e^{-x^2-c_{1)}-1}