What is the integral from 0 to 4 of 0.125x^2 ?

The integral from 0 to 4 of 0.125x^2 is 2.66666…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 0.125x^2

\int_{0}^{4} 0.125 x^{2} d x

2.66666 \dots

Solution steps

\int_{0}^{4} 0.125 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.125 \cdot \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= 0.125 [\frac{x ^{3}}{3}]_{0}^{4}

Simplify

= 0.125 [0.33333 \dots x^{3}]_{0}^{4}

Compute the boundaries:

21.33333 \dots

= 0.125 \cdot 21.33333 \dots

Simplify

= 2.66666 \dots

y^{^{''}} + 4 y = sin (x)

\frac{2 x ^{2} + 1}{x ^{2} + 8}

\int_{0}^{1} ln (x^{2} + 1) d x

\int \frac{1}{x ^{2} + x + 1} d x

- \frac{3 ( z ^{2} + 1 )}{z ^{2}}

What is the integral from 0 to 4 of 0.125x^2 ?
The integral from 0 to 4 of 0.125x^2 is 2.66666…