What is the tangent of f(x)=sqrt(14-x),\at x=5 ?

The tangent of f(x)=sqrt(14-x),\at x=5 is y=-1/6 x+23/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(14-x),\at x=5

tangent of

f (x) = 14 - x, at x = 5

y = - \frac{1}{6} x + \frac{23}{6}

Solution steps

Find the tangent point:

(5, 3)

Find the slope of

f (x) = 14 - x : \frac{df ( x )}{d x} = - \frac{1}{2 14 - x}

Compute the slope of

f (x) = 14 - x

x = 5 : m = - \frac{1}{6}

Find the line with slope m=

- \frac{1}{6}

and passing through

(5, 3) : y = - \frac{1}{6} x + \frac{23}{6}

y = - \frac{1}{6} x + \frac{23}{6}

\frac{\partial}{\partial x} (\frac{1}{x} + \frac{1}{y})

\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{\frac{3}{2}})

e^{- 3 x^{2}}

\int \frac{1}{4 t} d t

x \to 6 lim (f (x) - g (x))

What is the tangent of f(x)=sqrt(14-x),\at x=5 ?
The tangent of f(x)=sqrt(14-x),\at x=5 is y=-1/6 x+23/6