What is the derivative of x^3-5x^2+7x-3 ?

The derivative of x^3-5x^2+7x-3 is 3x^2-10x+7

What is the first derivative of x^3-5x^2+7x-3 ?

The first derivative of x^3-5x^2+7x-3 is 3x^2-10x+7

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\frac{d}{d x} (x^{3} - 5 x^{2} + 7 x - 3)

3 x^{2} - 10 x + 7

Solution steps

\frac{d}{d x} (x^{3} - 5 x^{2} + 7 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (3) = 0

= 3 x^{2} - 10 x + 7 - 0

Simplify

= 3 x^{2} - 10 x + 7

\frac{\partial}{\partial x} (x^{2} y - \frac{1}{x y})

\frac{d}{d x} (arccot (x))

f (x) = x^{2} 9 - x^{2}

- \frac{1}{( 1 + t ) ^{2}}

6 y^{^{''}} - y^{^{'}} - y = 0

What is the derivative of x^3-5x^2+7x-3 ?
The derivative of x^3-5x^2+7x-3 is 3x^2-10x+7
What is the first derivative of x^3-5x^2+7x-3 ?
The first derivative of x^3-5x^2+7x-3 is 3x^2-10x+7