What is (\partial)/(\partial x)(9x^2y^2) ?

The answer to (\partial)/(\partial x)(9x^2y^2) is 18xy^2

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(\partial)/(\partial x)(9x^2y^2)

\frac{\partial}{\partial x} (9 x^{2} y^{2})

18 x y^{2}

Solution steps

\frac{\partial}{\partial x} (9 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 y^{2} \cdot 2 x^{2 - 1}

Simplify

= 18 x y^{2}

\int (x^{2} e^{2 x} - 3 x e^{2 x} + 5 e^{2 x}) d x

\int_{2}^{6} 8 d x

x \to 0 lim (3 sin (x) - 1)

\frac{2 x + 5}{x}

\frac{d}{d x} (\frac{x ^{3}}{f ( x )})

What is (\partial)/(\partial x)(9x^2y^2) ?
The answer to (\partial)/(\partial x)(9x^2y^2) is 18xy^2