What is the solution for (dy)/(dx)=sin(19x) ?

The solution for (dy)/(dx)=sin(19x) is y=-1/19 cos(19x)+c_{1}

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(dy)/(dx)=sin(19x)

\frac{d y}{d x} = sin (19 x)

y = - \frac{1}{19} cos (19 x) + c_{1}

Solution steps

\frac{d y}{d x} = sin (19 x)

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = sin (19 x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (19 x) d x

\int sin (19 x) d x = - \frac{1}{19} cos (19 x) + c_{1}

y = - \frac{1}{19} cos (19 x) + c_{1}

\int_{4}^{5} t t - 4 d t

y = 6 x - 2

\frac{\partial}{\partial x} (arctan (x \cdot t))

2^{t}

\int \frac{( e ^{x} )}{x} d x

What is the solution for (dy)/(dx)=sin(19x) ?
The solution for (dy)/(dx)=sin(19x) is y=-1/19 cos(19x)+c_{1}