What is (\partial}{\partial y}(\frac{y^4)/x) ?

The answer to (\partial}{\partial y}(\frac{y^4)/x) is (4y^3)/x

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(\partial}{\partial y}(\frac{y^4)/x)

\frac{\partial}{\partial y} (\frac{y ^{4}}{x})

\frac{4 y ^{3}}{x}

Solution steps

\frac{\partial}{\partial y} (\frac{y ^{4}}{x})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x} \frac{\partial}{\partial y} (y^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{x} \cdot 4 y^{4 - 1}

Simplify

\frac{1}{x} \cdot 4 y^{4 - 1} : \frac{4 y ^{3}}{x}

= \frac{4 y ^{3}}{x}

\frac{d}{d s} (s + t)

x \to \infty lim (538 \cdot x)

\int x^{4} ln (4 x) d x

x \to - 6 - lim (\frac{1}{( x + 6 ) ^{4}})

n = 0 \sum \infty ln (\frac{n + 1}{n})

What is (\partial}{\partial y}(\frac{y^4)/x) ?
The answer to (\partial}{\partial y}(\frac{y^4)/x) is (4y^3)/x