What is the d/(dt)(sqrt(6)t^2) ?

The d/(dt)(sqrt(6)t^2) is 2sqrt(6)t

What is the first d/(dt)(sqrt(6)t^2) ?

The first d/(dt)(sqrt(6)t^2) is 2sqrt(6)t

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\frac{d}{d t} (6 t^{2})

26 t

Solution steps

\frac{d}{d t} (6 t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 \cdot 2 t^{2 - 1}

Simplify

= 26 t

\frac{d}{d x} ((x + 1)^{2 x})

\int \frac{sec ^{2} ( 2 t )}{5 + 3 tan ( 2 t )} d t

\frac{d}{d x} (\frac{x ^{2} - 3 x}{2})

f (x) = 3 x^{2} - x^{3}, at x = 1

\frac{d}{d x} (- 3 sin (x) - 2)

What is the d/(dt)(sqrt(6)t^2) ?
The d/(dt)(sqrt(6)t^2) is 2sqrt(6)t
What is the first d/(dt)(sqrt(6)t^2) ?
The first d/(dt)(sqrt(6)t^2) is 2sqrt(6)t