What is the derivative of (\sqrt[3]{x}-3/(x-3)) ?

The derivative of (\sqrt[3]{x}-3/(x-3)) is (x-3-3x^{2/3}(\sqrt[3]{x}-3))/(3x^{2/3)(x-3)^2}

What is the first derivative of (\sqrt[3]{x}-3/(x-3)) ?

The first derivative of (\sqrt[3]{x}-3/(x-3)) is (x-3-3x^{2/3}(\sqrt[3]{x}-3))/(3x^{2/3)(x-3)^2}

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Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 3) = 1

Simplify

\frac{\partial}{\partial x} (\frac{1}{( x - y ) ^{2}})

\frac{10 x ^{3} - 6 x ^{2} + 3}{4 x ^{2} - 6 x + 3}

x \to \infty lim (- \frac{1}{3} c e^{- 3 (x)})

\int (\frac{2}{x} - 4 e^{x}) d x

\frac{d}{d x} ((\frac{1}{x ^{2}}) d x)

What is the derivative of (\sqrt[3]{x}-3/(x-3)) ?
The derivative of (\sqrt[3]{x}-3/(x-3)) is (x-3-3x^{2/3}(\sqrt[3]{x}-3))/(3x^{2/3)(x-3)^2}
What is the first derivative of (\sqrt[3]{x}-3/(x-3)) ?
The first derivative of (\sqrt[3]{x}-3/(x-3)) is (x-3-3x^{2/3}(\sqrt[3]{x}-3))/(3x^{2/3)(x-3)^2}