What is area-2x^3+23x^2-33x-108,[0,x] ?

The answer to area-2x^3+23x^2-33x-108,[0,x] is 73261/96

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area-2x^3+23x^2-33x-108,[0,x]

area

- 2 x^{3} + 23 x^{2} - 33 x - 108, [0, x]

\frac{73261}{96}

Decimal Notation

763.13541 \dots

Solution steps

Apply the area formula:

\int_{- \frac{3}{2}}^{9} - 2 x^{3} + 23 x^{2} - 33 x - 108 d x

Solve

\int_{- \frac{3}{2}}^{9} - 2 x^{3} + 23 x^{2} - 33 x - 108 d x : \frac{73261}{96}

The area is:

= \frac{73261}{96}

t \frac{d y}{d t} = 2 t e^{t} - y + 6 t^{2}

\int 2 e^{6} d x

\int 1 + x d x

x \to 8 lim (\frac{x}{x ^{2} - 64})

x \frac{d y}{d x} + y^{2} + y = 0

What is area-2x^3+23x^2-33x-108,[0,x] ?
The answer to area-2x^3+23x^2-33x-108,[0,x] is 73261/96