What is the first d/(dy)(e^{2y}) ?

The first d/(dy)(e^{2y}) is e^{2y}*2

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d/(dy)(e^{2y})

\frac{d}{d y} (e^{2 y})

e^{2 y} \cdot 2

Solution steps

\frac{d}{d y} (e^{2 y})

Apply the chain rule:

e^{2 y} \frac{d}{d y} (2 y)

= e^{2 y} \frac{d}{d y} (2 y)

\frac{d}{d y} (2 y) = 2

= e^{2 y} \cdot 2

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