What is the sum from n=1 to infinity of 1/(2+n) ?

The sum from n=1 to infinity of 1/(2+n) is diverges

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sum from n=1 to infinity of 1/(2+n)

n = 1 \sum \infty \frac{1}{2 + n}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{2 + n}

Apply Series Integral Test:

diverges

= diverges

x \to 0 lim (\frac{1 - e ^{2 x}}{x})

\int_{- \infty}^{8} r e^{\frac{r}{2}} d r

\frac{d}{d t} (sin (π t))

\frac{\partial}{\partial y} (sin^{3} (x^{2} y))

\int_{- 1}^{1} (x^{2} + 1)^{2} d x

What is the sum from n=1 to infinity of 1/(2+n) ?
The sum from n=1 to infinity of 1/(2+n) is diverges