What is the derivative of (x^3+x^6) ?

The derivative of (x^3+x^6) is 6(x^3+x)^5(3x^2+1)

What is the first derivative of (x^3+x^6) ?

The first derivative of (x^3+x^6) is 6(x^3+x)^5(3x^2+1)

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\frac{d}{d x} ((x^{3} + x)^{6})

6 (x^{3} + x)^{5} (3 x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{3} + x)^{6})

Apply the chain rule:

6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

= 6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

\frac{d}{d x} (x^{3} + x) = 3 x^{2} + 1

= 6 (x^{3} + x)^{5} (3 x^{2} + 1)

\frac{d}{d x} (x (6^{- 2 x}))

e^{x^{4}}, 3

\int_{- π}^{π} x^{3} sin (n x) d x

7 - x - x^{2}

\frac{d}{d x} (\frac{x}{5 + x ^{2}})

What is the derivative of (x^3+x^6) ?
The derivative of (x^3+x^6) is 6(x^3+x)^5(3x^2+1)
What is the first derivative of (x^3+x^6) ?
The first derivative of (x^3+x^6) is 6(x^3+x)^5(3x^2+1)