What is the derivative of y=ln^2(x+3) ?

The derivative of y=ln^2(x+3) is (2ln(x+3))/(x+3)

What is the first derivative of y=ln^2(x+3) ?

The first derivative of y=ln^2(x+3) is (2ln(x+3))/(x+3)

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derivative of

y = ln^{2} (x + 3)

\frac{2 ln ( x + 3 )}{x + 3}

Solution steps

\frac{d}{d x} (ln^{2} (x + 3))

Apply the chain rule:

2 ln (x + 3) \frac{d}{d x} (ln (x + 3))

= 2 ln (x + 3) \frac{d}{d x} (ln (x + 3))

\frac{d}{d x} (ln (x + 3)) = \frac{1}{x + 3}

= 2 ln (x + 3) \frac{1}{x + 3}

Simplify

2 ln (x + 3) \frac{1}{x + 3} : \frac{2 ln ( x + 3 )}{x + 3}

= \frac{2 ln ( x + 3 )}{x + 3}

\frac{\partial}{\partial x} (e^{x^{2} y})

2 y^{^{''}} + 12 y^{^{'}} + 50 y = 0, y (0) = 0, y^{^{'}} (0) = - 8

y = x + 8, (8, 4)

\int 8 e^{t} - 5 d t

\frac{8 x ^{2} + 18 x}{( 9 + 8 x ) ^{2}}

What is the derivative of y=ln^2(x+3) ?
The derivative of y=ln^2(x+3) is (2ln(x+3))/(x+3)
What is the first derivative of y=ln^2(x+3) ?
The first derivative of y=ln^2(x+3) is (2ln(x+3))/(x+3)