What is the limit as x approaches c/(2^-) of [2x-4] ?

The limit as x approaches c/(2^-) of [2x-4] is 2^1c-4

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limit as x approaches c/(2^-) of [2x-4]

x \to \frac{c}{2 ^{-}} lim ([2 x - 4])

2^{1} c - 4

Solution steps

x \to \frac{c}{2 ^{-}} lim (2 x - 4)

Plug in the value

x = \frac{c}{2 ^{-}}

= 2 \cdot \frac{c}{2 ^{-}} - 4

2 \cdot \frac{c}{2 ^{-}} = 2^{1} c

= 2^{1} c - 4

(y^{2} + x y^{2}) y^{^{'}} = 1

g (x) = \frac{3 x + 1}{( 2 x ^{2} - 5 ) ^{2}}

(1 + e^{t})^{2}

\frac{\partial}{\partial x} (8 + x ln (x y - 5))

\int \frac{x ^{2}}{u} d u

What is the limit as x approaches c/(2^-) of [2x-4] ?
The limit as x approaches c/(2^-) of [2x-4] is 2^1c-4