What is (\partial)/(\partial y)(e^x+y^2) ?

The answer to (\partial)/(\partial y)(e^x+y^2) is 2y

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(\partial)/(\partial y)(e^x+y^2)

\frac{\partial}{\partial y} (e^{x} + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (e^{x} + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x}) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (e^{x}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

h (x) = \frac{7}{x ^{2}}

\frac{( s + 1 )}{( s \cdot ( s ^{2} + s + 1 ) )}

n = 5 \sum \infty \frac{1}{2 ^{2 n}}

f (x) = 5 - 8 x^{2}

\frac{d y}{d x} = 7 x y

What is (\partial)/(\partial y)(e^x+y^2) ?
The answer to (\partial)/(\partial y)(e^x+y^2) is 2y