What is the tangent of f(x)= 3/x ,(-5,-3/5) ?

The tangent of f(x)= 3/x ,(-5,-3/5) is y=-3/25 x-6/5

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tangent of f(x)= 3/x ,(-5,-3/5)

tangent of

f (x) = \frac{3}{x}, (- 5, - \frac{3}{5})

y = - \frac{3}{25} x - \frac{6}{5}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

f (x) = \frac{3}{x}

(- 5, - \frac{3}{5}) : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(- 5, - \frac{3}{5}) : y = - \frac{3}{25} x - \frac{6}{5}

y = - \frac{3}{25} x - \frac{6}{5}

n = 0 \sum \infty sin (\frac{1}{n})

\int x^{2} 5 x + 8 d x

6 (x - 3)^{\frac{2}{3}}

\int_{1}^{9} \frac{1}{x - 5} d x

x \to 0 lim (x cos (\frac{1}{x}))

What is the tangent of f(x)= 3/x ,(-5,-3/5) ?
The tangent of f(x)= 3/x ,(-5,-3/5) is y=-3/25 x-6/5