What is the limit as x approaches 0+of 1-ln(x) ?

The limit as x approaches 0+of 1-ln(x) is infinity

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limit as x approaches 0+of 1-ln(x)

x \to 0 + lim (1 - ln (x))

\infty

Solution steps

x \to 0 + lim (1 - ln (x))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (1) - x \to 0 + lim (ln (x))

x \to 0 + lim (1) = 1

x \to 0 + lim (ln (x)) = - \infty

= 1 - (- \infty)

Simplify

1 - (- \infty) : \infty

= \infty

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\int_{1}^{3} \frac{x ^{2} - 1}{x} d x

\int arctan (x - 1) d x

What is the limit as x approaches 0+of 1-ln(x) ?
The limit as x approaches 0+of 1-ln(x) is infinity