What is (\partial)/(\partial x)(x^2+8y^2+9z^2-7) ?

The answer to (\partial)/(\partial x)(x^2+8y^2+9z^2-7) is 2x

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(\partial)/(\partial x)(x^2+8y^2+9z^2-7)

\frac{\partial}{\partial x} (x^{2} + 8 y^{2} + 9 z^{2} - 7)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + 8 y^{2} + 9 z^{2} - 7)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (8 y^{2}) + \frac{\partial}{\partial x} (9 z^{2}) - \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (8 y^{2}) = 0

\frac{\partial}{\partial x} (9 z^{2}) = 0

\frac{\partial}{\partial x} (7) = 0

= 2 x + 0 + 0 - 0

Simplify

= 2 x

\frac{d}{d x} (f (x) (5 x^{2} + 3))

\int x^{3} x^{4} + 10 d x

4 y^{^{''}} + 4 y^{^{'}} + 9 y = 0

\int_{2}^{3} \frac{1}{x ^{2} - 1} d x

\int (y - 2)^{2} d y

What is (\partial)/(\partial x)(x^2+8y^2+9z^2-7) ?
The answer to (\partial)/(\partial x)(x^2+8y^2+9z^2-7) is 2x