What is the solution for y^'=((y^4-1))/(xy^3) ?

The solution for y^'=((y^4-1))/(xy^3) is y=\sqrt[4]{c_{1}x^4+1},y=-\sqrt[4]{c_{1}x^4+1}

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y^'=((y^4-1))/(xy^3)

y^{^{'}} = \frac{( y ^{4} - 1 )}{x y ^{3}}

Solution steps

y^{'} (x) = \frac{( y ^{4} - 1 )}{x y ^{3}}

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What is the solution for y^'=((y^4-1))/(xy^3) ?
The solution for y^'=((y^4-1))/(xy^3) is y=\sqrt[4]{c_{1}x^4+1},y=-\sqrt[4]{c_{1}x^4+1}