What is the limit as x approaches 0+of x^{16x} ?

The limit as x approaches 0+of x^{16x} is 1

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limit as x approaches 0+of x^{16x}

x \to 0 + lim (x^{16 x})

1

Solution steps

x \to 0 + lim (x^{16 x})

Apply exponent rules

= x \to 0 + lim (e^{16 x l n (x)})

Apply the Limit Chain Rule:

1

= 1

y^{^{'''}} + 2 x \cdot x = 0

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What is the limit as x approaches 0+of x^{16x} ?
The limit as x approaches 0+of x^{16x} is 1