What is (\partial)/(\partial x)(x^3+y^2) ?

The answer to (\partial)/(\partial x)(x^3+y^2) is 3x^2

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(\partial)/(\partial x)(x^3+y^2)

\frac{\partial}{\partial x} (x^{3} + y^{2})

3 x^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (y^{2}) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

x^{2} y^{^{''}} + 15 x y^{^{'}} + 49 y = 0

\frac{1}{s ^{2} + 10.1 s + 1}

\int x - 2 d x

f (x) = 3 x + x^{\frac{4}{3}}

x \to 0 + lim (\frac{1}{x} \cdot e^{\frac{1}{x}})

What is (\partial)/(\partial x)(x^3+y^2) ?
The answer to (\partial)/(\partial x)(x^3+y^2) is 3x^2