What is the derivative of f(x)=3cos(2x) ?

The derivative of f(x)=3cos(2x) is -6sin(2x)

What is the first derivative of f(x)=3cos(2x) ?

The first derivative of f(x)=3cos(2x) is -6sin(2x)

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derivative of

f (x) = 3 cos (2 x)

- 6 sin (2 x)

Solution steps

\frac{d}{d x} (3 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 3 (- sin (2 x) \cdot 2)

Simplify

= - 6 sin (2 x)

y = \frac{8}{1 + x ^{4}}, y = 4 x^{2}

f (x) = \frac{1}{x - 4}

\int sec (d) x d x

\int (\frac{2}{x} + \frac{x}{2}) d x

\int \frac{( 4 + 3 x ^{2} )}{x ^{3}} d x

What is the derivative of f(x)=3cos(2x) ?
The derivative of f(x)=3cos(2x) is -6sin(2x)
What is the first derivative of f(x)=3cos(2x) ?
The first derivative of f(x)=3cos(2x) is -6sin(2x)