What is the derivative of arcsec(2x+3) ?

The derivative of arcsec(2x+3) is 1/(sqrt((2x+3)^2)\sqrt{x^2+3x+2)}

What is the first derivative of arcsec(2x+3) ?

The first derivative of arcsec(2x+3) is 1/(sqrt((2x+3)^2)\sqrt{x^2+3x+2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

arcsec (2 x + 3)

\frac{1}{( 2 x + 3 ) ^{2} x ^{2} + 3 x + 2}

Solution steps

\frac{d}{d x} (arcsec (2 x + 3))

Apply the chain rule:

\frac{1}{( 2 x + 3 ) ^{2} ( 2 x + 3 ) ^{2} - 1} \frac{d}{d x} (2 x + 3)

= \frac{1}{( 2 x + 3 ) ^{2} ( 2 x + 3 ) ^{2} - 1} \frac{d}{d x} (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

= \frac{1}{( 2 x + 3 ) ^{2} ( 2 x + 3 ) ^{2} - 1} \cdot 2

Simplify

\frac{1}{( 2 x + 3 ) ^{2} ( 2 x + 3 ) ^{2} - 1} \cdot 2 : \frac{1}{( 2 x + 3 ) ^{2} x ^{2} + 3 x + 2}

= \frac{1}{( 2 x + 3 ) ^{2} x ^{2} + 3 x + 2}

\frac{d}{d x} (ln (2 x^{3} + 8 x))

\int 8^{2 x + 6} d x

\frac{8}{0.65 s + 1}

\frac{x}{1 + x ^{2}}

\int \frac{3 x - 4}{x ^{2} - x - 6} d x

What is the derivative of arcsec(2x+3) ?
The derivative of arcsec(2x+3) is 1/(sqrt((2x+3)^2)\sqrt{x^2+3x+2)}
What is the first derivative of arcsec(2x+3) ?
The first derivative of arcsec(2x+3) is 1/(sqrt((2x+3)^2)\sqrt{x^2+3x+2)}