What is area y=(x^2)/2-4x+6,y= x/2-1 ?

The answer to area y=(x^2)/2-4x+6,y= x/2-1 is 125/12

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area y=(x^2)/2-4x+6,y= x/2-1

area

y = \frac{x ^{2}}{2} - 4 x + 6, y = \frac{x}{2} - 1

\frac{125}{12}

Decimal Notation

10.41666 \dots

Solution steps

Apply the area formula:

\int_{2}^{7} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x

Solve

\int_{2}^{7} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x : \frac{125}{12}

The area is:

= \frac{125}{12}

x^{\frac{1}{2}} + y^{\frac{1}{2}} = 9

\frac{d}{d x} (\frac{x + 9}{x - 9})

x \to 0 lim (\frac{( 1 + x ) ^{7} - 1}{x})

\frac{\partial}{\partial x} (ln (e^{x} + e^{y} + e^{z}))

\int x^{3} sin (4 x) d x

What is area y=(x^2)/2-4x+6,y= x/2-1 ?
The answer to area y=(x^2)/2-4x+6,y= x/2-1 is 125/12