What is the integral of e^{2x}(2) ?

The integral of e^{2x}(2) is e^{2x}+C

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integral of e^{2x}(2)

\int e^{2 x} (2) d x

e^{2 x} + C

Solution steps

\int e^{2 x} \cdot 2 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{2 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{2} d u

= 2 \cdot \int e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 2 \cdot \frac{1}{2} e^{u}

Substitute back

u = 2 x

= 2 \cdot \frac{1}{2} e^{2 x}

Simplify

2 \cdot \frac{1}{2} e^{2 x} : e^{2 x}

= e^{2 x}

Add a constant to the solution

= e^{2 x} + C

y^{^{'}} = y^{\frac{2}{3}}

\int \frac{4}{- 3 x} d x

\frac{d}{d x} (I n^{2})

f (x) = \frac{x}{( x ^{2} + 15 x + 50 )}

1 - x, y = 2, - 1, 1