What is (\partial)/(\partial x)(1+x) ?

The answer to (\partial)/(\partial x)(1+x) is 1

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(\partial)/(\partial x)(1+x)

\frac{\partial}{\partial x} (1 + x)

1

Solution steps

\frac{\partial}{\partial x} (1 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 + 1

Simplify

= 1

\frac{d v}{d x} = - 2 v - 32

\frac{\partial}{\partial y} (cos (x) y)

\frac{\partial}{\partial x} (e^{x + 1})

\frac{d}{d x} (ln (x + x^{2} - 6))

\int + \frac{40}{1 - cos ( 8 x )} d x

What is (\partial)/(\partial x)(1+x) ?
The answer to (\partial)/(\partial x)(1+x) is 1