What is the tangent of y= pi/((2x)^4) ?

The tangent of y= pi/((2x)^4) is y=-pi/(4a_{0)^5}x+(5pi)/(16a_{0)^4}

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tangent of y= pi/((2x)^4)

tangent of

y = \frac{π}{( 2 x ) ^{4}}

y = - \frac{π}{4 a _{0}^{5}} x + \frac{5 π}{16 a _{0}^{4}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{π}{16 a _{0}^{4}})

Find the slope of

y = \frac{π}{( 2 x ) ^{4}} : \frac{d y}{d x} = - \frac{π}{4 x ^{5}}

Compute the slope of

y = \frac{π}{( 2 x ) ^{4}}

x = a_{0} : m = - \frac{π}{4 a _{0}^{5}}

Find the line with slope m=

- \frac{π}{4 a _{0}^{5}}

and passing through

(a_{0}, \frac{π}{16 a _{0}^{4}}) : y = - \frac{π}{4 a _{0}^{5}} x + \frac{5 π}{16 a _{0}^{4}}

y = - \frac{π}{4 a _{0}^{5}} x + \frac{5 π}{16 a _{0}^{4}}

\int \frac{2}{x ^{2} + 9} d x

\frac{x d y}{d x} = 2 y

\frac{d y}{d x}, y = 2 9^{x}

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 2

x \to 1 lim (x^{2} + 1)

What is the tangent of y= pi/((2x)^4) ?
The tangent of y= pi/((2x)^4) is y=-pi/(4a_{0)^5}x+(5pi)/(16a_{0)^4}