en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^'x-5x=25

Solution

x^{^{'}} x - 5 x = 25

Solution

x = - 5 W (- \frac{1}{5 e ^{\frac{5 t + c _{1}}{5}}}) - 5

Solution steps

x^{'} (t) x - 5 x = 25

Solve separable ODE:

x = - 5 W (- \frac{1}{5 e ^{\frac{5 t + c _{1}}{5}}}) - 5

x = - 5 W (- \frac{1}{5 e ^{\frac{5 t + c _{1}}{5}}}) - 5

Popular Examples

derivative of f(x)= x/(x+7)derivative of

f (x) = \frac{x}{x + 7}

y^{'''}+y^{''}=x-e^{-x}

y^{^{'''}} + y^{^{''}} = x - e^{- x}

integral of xsin(1/11 x)

\int x sin (\frac{1}{11} x) d x

(\partial)/(\partial y)(z^2e^{xy})

\frac{\partial}{\partial y} (z^{2} e^{x y})

y^{''}+16y^'+65y=0

y^{^{''}} + 16 y^{^{'}} + 65 y = 0

Frequently Asked Questions (FAQ)

What is the solution for x^'x-5x=25 ?
The solution for x^'x-5x=25 is x=-5\W(-1/(5e^{(5t+c_{1))/5}})-5