What is the derivative of 2cos(2x-1) ?

The derivative of 2cos(2x-1) is -4sin(2x)

What is the first derivative of 2cos(2x-1) ?

The first derivative of 2cos(2x-1) is -4sin(2x)

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\frac{d}{d x} (2 cos (2 x) - 1)

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (2 x)) - \frac{d}{d x} (1)

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

\frac{d}{d x} (1) = 0

= - 4 sin (2 x) - 0

Simplify

= - 4 sin (2 x)

x \to 4 lim (x - x^{2})

\frac{d}{d y} (4 arctan (\frac{x}{y}))

\frac{\partial}{\partial x} (4 y^{2} + 7 x^{2})

x^{2} - 3, 1

What is the derivative of 2cos(2x-1) ?
The derivative of 2cos(2x-1) is -4sin(2x)
What is the first derivative of 2cos(2x-1) ?
The first derivative of 2cos(2x-1) is -4sin(2x)