What is the solution for (dy)/(dx)(x^2+1)+7x(y-1)=0 ?

The solution for (dy)/(dx)(x^2+1)+7x(y-1)=0 is y=(c_{1})/((x^2+1)^{7/2)}+1

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(dy)/(dx)(x^2+1)+7x(y-1)=0

\frac{d y}{d x} (x^{2} + 1) + 7 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

Solution steps

\frac{d y}{d x} (x^{2} + 1) + 7 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{7}{2}}} + 1

\int_{0}^{1} \frac{41}{x ^{5}} d x

\frac{d}{d x} (\frac{x}{x - 37})

f (x) = sin (3 x^{2})

\int \frac{1}{20} d x

f (x) = e^{x^{2}}

What is the solution for (dy)/(dx)(x^2+1)+7x(y-1)=0 ?
The solution for (dy)/(dx)(x^2+1)+7x(y-1)=0 is y=(c_{1})/((x^2+1)^{7/2)}+1