What is the solution for y^{''}+49y=sin(7t) ?

The solution for y^{''}+49y=sin(7t) is y=c_{1}cos(7t)+c_{2}sin(7t)-(tcos(7t))/(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+49y=sin(7t)

y^{^{''}} + 49 y = sin (7 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{t cos ( 7 t )}{14}

Solution steps

y^{''} (t) + 49 y = sin (7 t)

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{t cos ( 7 t )}{14}

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{t cos ( 7 t )}{14}

x \to 1 lim (\frac{x - 8 + 7}{x - 1})

y = \frac{x}{2 x + \frac{- 4}{x}}

9 y y^{^{'}} + 4 x = 0

e^{c o s (x)}

\frac{d}{d x} (csc^{9} (x))

What is the solution for y^{''}+49y=sin(7t) ?
The solution for y^{''}+49y=sin(7t) is y=c_{1}cos(7t)+c_{2}sin(7t)-(tcos(7t))/(14)