What is the tangent of (4x)/(x+2)(2.2) ?

The tangent of (4x)/(x+2)(2.2) is y=(17.6)/((a_{0)+2)^2}x+(8.8a_{0}^2)/((a_{0)+2)^2}

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tangent of (4x)/(x+2)(2.2)

tangent of

\frac{4 x}{x + 2} (2.2)

y = \frac{17.6}{( a _{0} + 2 ) ^{2}} x + \frac{8.8 a _{0}^{2}}{( a _{0} + 2 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{8.8 a _{0}}{a _{0} + 2})

Find the slope of

y = \frac{4 x}{x + 2} 2.2 : \frac{d y}{d x} = \frac{17.6}{( x + 2 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x + 2} 2.2

x = a_{0} : m = \frac{17.6}{( a _{0} + 2 ) ^{2}}

Find the line with slope m=

\frac{17.6}{( a _{0} + 2 ) ^{2}}

and passing through

(a_{0}, \frac{8.8 a _{0}}{a _{0} + 2}) : y = \frac{17.6}{( a _{0} + 2 ) ^{2}} x + \frac{8.8 a _{0}^{2}}{( a _{0} + 2 ) ^{2}}

y = \frac{17.6}{( a _{0} + 2 ) ^{2}} x + \frac{8.8 a _{0}^{2}}{( a _{0} + 2 ) ^{2}}

\frac{1}{10 x}, at x = 9

\frac{d}{d x} (\frac{x ^{3}}{x ^{2} - 9})

\int ln (x) d x

\int \frac{t ^{3} - 8 t + 1}{( 2 t ) ^{4}} d t

y = ln (\frac{3 + e ^{x}}{3 - e ^{x}})

What is the tangent of (4x)/(x+2)(2.2) ?
The tangent of (4x)/(x+2)(2.2) is y=(17.6)/((a_{0)+2)^2}x+(8.8a_{0}^2)/((a_{0)+2)^2}