What is area y^2-2x=9,x-y=3[-4.5,8] ?

The answer to area y^2-2x=9,x-y=3[-4.5,8] is No Solution

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area y^2-2x=9,x-y=3[-4.5,8]

area

y^{2} - 2 x = 9, x - y = 3 [- 4.5, 8]

No Solution

Solution steps

Isolate

y

for

y^{2} - 2 x = 9 : y = 9 + 2 x, y = - 9 + 2 x

Isolate

y

for

x - y = 3 [- 4.5, 8] : y = \frac{3 [ - 4.5 , 8 ]}{- 1} - \frac{x}{- 1}

f_{1} (x) = 9 + 2 x

f_{2} (x) = - 9 + 2 x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

9 + 2 x = - 9 + 2 x : x = - \frac{9}{2}

9 + 2 x = \frac{3 [ - 4.5 , 8 ]}{- 1} - \frac{x}{- 1} :

No Solution for

x \in R

- 9 + 2 x = \frac{3 [ - 4.5 , 8 ]}{- 1} - \frac{x}{- 1} :

No Solution for

x \in R

Curves not bounded

= No Solution

\frac{d}{d x} (ln (arctan (3 x^{3})))

\frac{d}{d x} (\frac{a}{x ^{2} + a ^{2}})

(1 + cos (t)) y^{^{'}} = (1 + e^{- y}) sin (t)

What is area y^2-2x=9,x-y=3[-4.5,8] ?
The answer to area y^2-2x=9,x-y=3[-4.5,8] is No Solution