What is the integral from 0 to 2 of 2^x ?

The integral from 0 to 2 of 2^x is 3/(ln(2))

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integral from 0 to 2 of 2^x

\int_{0}^{2} 2^{x} d x

\frac{3}{ln ( 2 )}

Decimal Notation

4.32808 \dots

Solution steps

\int_{0}^{2} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{0}^{2}

Compute the boundaries:

\frac{3}{ln ( 2 )}

= \frac{3}{ln ( 2 )}

\int \frac{1}{3 x ^{2} + 1} d x

y d u + (2 y - u) d y = 0

\int \frac{1}{4 x + 2} d x

k = 0 \sum \infty (2 k + 1) x^{2 k}

y^{^{'}} - y^{2} = 1

What is the integral from 0 to 2 of 2^x ?
The integral from 0 to 2 of 2^x is 3/(ln(2))