What is the sum from n=1 to infinity of (2n)/(5n-7) ?

The sum from n=1 to infinity of (2n)/(5n-7) is diverges

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sum from n=1 to infinity of (2n)/(5n-7)

n = 1 \sum \infty \frac{2 n}{5 n - 7}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{5 n - 7}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{5 n - 7}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

\frac{d}{d x} (2^{x^{3} - 2} - \frac{1}{x ^{2}})

\frac{\partial}{\partial x} (\frac{6}{x ^{3}})

\frac{d}{d x} (\frac{20}{x ^{3}})

\int 3 x^{2} - 5 x + 2 d x

\int_{0}^{\infty} 6 e^{- 3 x} d x

What is the sum from n=1 to infinity of (2n)/(5n-7) ?
The sum from n=1 to infinity of (2n)/(5n-7) is diverges