What is the tangent of y=5x-2x^2-x ?

The tangent of y=5x-2x^2-x is y=(-4a_{0}+4)x+2a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=5x-2x^2-x

tangent of

y = 5 x - 2 x^{2} - x

y = (- 4 a_{0} + 4) x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{2} + 4 a_{0})

Find the slope of

y = 5 x - 2 x^{2} - x : \frac{d y}{d x} = - 4 x + 4

Compute the slope of

y = 5 x - 2 x^{2} - x

x = a_{0} : m = - 4 a_{0} + 4

Find the line with slope m=

- 4 a_{0} + 4

and passing through

(a_{0}, - 2 a_{0}^{2} + 4 a_{0}) : y = (- 4 a_{0} + 4) x + 2 a_{0}^{2}

y = (- 4 a_{0} + 4) x + 2 a_{0}^{2}

x^{\frac{5}{7}}

\int \frac{1}{x ^{- \frac{1}{2}} - x} d x

\frac{d y}{d x} + 2 y = e^{x} y^{- 4}

\frac{d y}{d x} = 2 x y + x y^{2}

n = 0 \sum \infty 2 + (0.86)^{n}

What is the tangent of y=5x-2x^2-x ?
The tangent of y=5x-2x^2-x is y=(-4a_{0}+4)x+2a_{0}^2