What is the derivative of 9\sqrt[3]{x} ?

The derivative of 9\sqrt[3]{x} is 3/(x^{2/3)}

What is the first derivative of 9\sqrt[3]{x} ?

The first derivative of 9\sqrt[3]{x} is 3/(x^{2/3)}

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\frac{3}{x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 9 \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

9 \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{3}{x ^{\frac{2}{3}}}

= \frac{3}{x ^{\frac{2}{3}}}

\int x \cdot a c \cdot e^{- a c x + ab c - 1} d x

\frac{d}{d x} (4 x^{4} ln (x))

\int \frac{2 x ^{2}}{( 4 + x ^{2} ) ^{2}} d x

y^{^{'}} = x - x^{2}

f (x) = 10 x + ln (10 x)

What is the derivative of 9\sqrt[3]{x} ?
The derivative of 9\sqrt[3]{x} is 3/(x^{2/3)}
What is the first derivative of 9\sqrt[3]{x} ?
The first derivative of 9\sqrt[3]{x} is 3/(x^{2/3)}