What is the derivative of f(x)=3cos(2ln(x)) ?

The derivative of f(x)=3cos(2ln(x)) is -(6sin(2ln(x)))/x

What is the first derivative of f(x)=3cos(2ln(x)) ?

The first derivative of f(x)=3cos(2ln(x)) is -(6sin(2ln(x)))/x

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derivative of

f (x) = 3 cos (2 ln (x))

- \frac{6 sin ( 2 ln ( x ) )}{x}

Solution steps

\frac{d}{d x} (3 cos (2 ln (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (2 ln (x)))

Apply the chain rule:

- sin (2 ln (x)) \frac{d}{d x} (2 ln (x))

= - sin (2 ln (x)) \frac{d}{d x} (2 ln (x))

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

= 3 (- sin (2 ln (x)) \frac{2}{x})

Simplify

3 (- sin (2 ln (x)) \frac{2}{x}) : - \frac{6 sin ( 2 ln ( x ) )}{x}

= - \frac{6 sin ( 2 ln ( x ) )}{x}

x \frac{d y}{d x} + y = x

y^{^{'}} + 6 y = e^{4 t}, y (0) = 2

\int \frac{x ^{2}}{20 - 4 x + x ^{2}} d x

\frac{d}{d x} (0.5 sin^{2} (x) - x + 1)

\frac{4}{( s + 1 ) ^{2}}

What is the derivative of f(x)=3cos(2ln(x)) ?
The derivative of f(x)=3cos(2ln(x)) is -(6sin(2ln(x)))/x
What is the first derivative of f(x)=3cos(2ln(x)) ?
The first derivative of f(x)=3cos(2ln(x)) is -(6sin(2ln(x)))/x