What is the solution for yln(x)(dy}{dx}=(\frac{(y+1))/x)^2 ?

The solution for yln(x)(dy}{dx}=(\frac{(y+1))/x)^2 is y=-1-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}})}

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yln(x)(dy}{dx}=(\frac{(y+1))/x)^2

y ln (x) \frac{d y}{d x} = (\frac{( y + 1 )}{x})^{2}

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

Solution steps

y ln (x) \frac{d y}{d x} = (\frac{( y + 1 )}{x})^{2}

Solve Bernoulli ODE:

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

(x^{2} - 7)^{2}

\frac{\partial}{\partial x} (ln (cos^{2} (x) + 1))

f (x) = \frac{x}{( 5 x - 4 ) ^{8}}, at x = 1

(- 2.2) (5.3)

y = x (x + 1)^{5}, (1, 32)

What is the solution for yln(x)(dy}{dx}=(\frac{(y+1))/x)^2 ?
The solution for yln(x)(dy}{dx}=(\frac{(y+1))/x)^2 is y=-1-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}})}