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Popular >

y^'+2y=4t,y(0)=3

Solution

y^{^{'}} + 2 y = 4 t, y (0) = 3

Solution

y = 2 t - 1 + \frac{4}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = 4 t

Solve linear ODE:

y = 2 t - 1 + \frac{4}{e ^{2 t}}

y = 2 t - 1 + \frac{4}{e ^{2 t}}

Popular Examples

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y^{''}+2y^'+17y=0

y^{^{''}} + 2 y^{^{'}} + 17 y = 0

derivative of 1/(sqrt(x^2+9))

\frac{d}{d x} (\frac{1}{x ^{2} + 9})

integral of (5x^2)/(x^2+7)

\int \frac{5 x ^{2}}{x ^{2} + 7} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=4t,y(0)=3 ?
The solution for y^'+2y=4t,y(0)=3 is y=2t-1+4/(e^{2t)}