What is the derivative of f(x)= 1/x-2x ?

The derivative of f(x)= 1/x-2x is -1/(x^2)-2

What is the first derivative of f(x)= 1/x-2x ?

The first derivative of f(x)= 1/x-2x is -1/(x^2)-2

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derivative of

f (x) = \frac{1}{x} - 2 x

- \frac{1}{x ^{2}} - 2

Solution steps

\frac{d}{d x} (\frac{1}{x} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (2 x) = 2

= - \frac{1}{x ^{2}} - 2

\frac{d}{d x} (\frac{3}{4} x^{2} - 5 x^{3})

\int \frac{1}{- 2 x} d x

cos^{2} (25 t)

5 x - 2 x

cos (\frac{2}{x})

What is the derivative of f(x)= 1/x-2x ?
The derivative of f(x)= 1/x-2x is -1/(x^2)-2
What is the first derivative of f(x)= 1/x-2x ?
The first derivative of f(x)= 1/x-2x is -1/(x^2)-2