What is the derivative of 2x^3-15x^2-36x ?

The derivative of 2x^3-15x^2-36x is 6x^2-30x-36

What is the first derivative of 2x^3-15x^2-36x ?

The first derivative of 2x^3-15x^2-36x is 6x^2-30x-36

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\frac{d}{d x} (2 x^{3} - 15 x^{2} - 36 x)

6 x^{2} - 30 x - 36

Solution steps

\frac{d}{d x} (2 x^{3} - 15 x^{2} - 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (15 x^{2}) - \frac{d}{d x} (36 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (15 x^{2}) = 30 x

\frac{d}{d x} (36 x) = 36

= 6 x^{2} - 30 x - 36

- 4 e^{- 5 x^{2}}

x \to 0 lim (tan (6 x))

\frac{d y}{d x} = 2 sec^{2} (x)

n = 0 \sum \infty e^{- na}

6^{s i n (π x)}

What is the derivative of 2x^3-15x^2-36x ?
The derivative of 2x^3-15x^2-36x is 6x^2-30x-36
What is the first derivative of 2x^3-15x^2-36x ?
The first derivative of 2x^3-15x^2-36x is 6x^2-30x-36