What is the integral of 0.06x^2-4.4x+60 ?

The integral of 0.06x^2-4.4x+60 is 0.02x^3-2.2x^2+60x+C

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integral of 0.06x^2-4.4x+60

\int 0.06 x^{2} - 4.4 x + 60 d x

0.02 x^{3} - 2.2 x^{2} + 60 x + C

Solution steps

\int 0.06 x^{2} - 4.4 x + 60 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.06 x^{2} d x - \int 4.4 x d x + \int 60 d x

\int 0.06 x^{2} d x = 0.02 x^{3}

\int 4.4 x d x = 2.2 x^{2}

\int 60 d x = 60 x

= 0.02 x^{3} - 2.2 x^{2} + 60 x

Add a constant to the solution

= 0.02 x^{3} - 2.2 x^{2} + 60 x + C

x \to 0 lim (2 x tan (3 x))

f (x) = x^{3} - 2 x^{2} - 3 x

\int_{1}^{8} 1 d x

\int_{0}^{1} 7 x e^{x^{2}} d x

y^{^{''}} - 6 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 1

What is the integral of 0.06x^2-4.4x+60 ?
The integral of 0.06x^2-4.4x+60 is 0.02x^3-2.2x^2+60x+C