What is the integral of tan^2(6t) ?

The integral of tan^2(6t) is -t+1/6 tan(6t)+C

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integral of tan^2(6t)

\int tan^{2} (6 t) d t

- t + \frac{1}{6} tan (6 t) + C

Solution steps

\int tan^{2} (6 t) d t

Rewrite using trig identities

= \int - 1 + sec^{2} (6 t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d t + \int sec^{2} (6 t) d t

\int 1 d t = t

\int sec^{2} (6 t) d t = \frac{1}{6} tan (6 t)

= - t + \frac{1}{6} tan (6 t)

Add a constant to the solution

= - t + \frac{1}{6} tan (6 t) + C

x^{\frac{3}{7}}

\frac{d y}{d x} + \frac{4 y}{x} = - 3 x

\int (2 x + 1) e^{3 x} d x

\frac{3}{x ^{13}}

What is the integral of tan^2(6t) ?
The integral of tan^2(6t) is -t+1/6 tan(6t)+C