What is the solution for (x^2+1)(dy)/(dx)+8x(y-1)=0 ?

The solution for (x^2+1)(dy)/(dx)+8x(y-1)=0 is y=(c_{1})/(x^8+4x^6+6x^4+4x^2+1)+1

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(x^2+1)(dy)/(dx)+8x(y-1)=0

(x^{2} + 1) \frac{d y}{d x} + 8 x (y - 1) = 0

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 8 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

y = \frac{c _{1}}{x ^{8} + 4 x ^{6} + 6 x ^{4} + 4 x ^{2} + 1} + 1

\int \frac{40 x ^{2}}{x ^{4} - 52 x ^{2} + 576} d x

(2, 3), (- 2, - 3)

\frac{d}{d x} (\frac{4}{2 x + 1})

f (x) = 2 x^{2} + x - 1, at x = 0

\frac{d}{d x} (lo g_{10} (\frac{x}{x ^{2} + 1}))

What is the solution for (x^2+1)(dy)/(dx)+8x(y-1)=0 ?
The solution for (x^2+1)(dy)/(dx)+8x(y-1)=0 is y=(c_{1})/(x^8+4x^6+6x^4+4x^2+1)+1