What is (\partial)/(\partial y)(4x^3y^3+4) ?

The answer to (\partial)/(\partial y)(4x^3y^3+4) is 12x^3y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(4x^3y^3+4)

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 4)

12 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 4)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{3} y^{3}) + \frac{\partial}{\partial y} (4)

\frac{\partial}{\partial y} (4 x^{3} y^{3}) = 12 x^{3} y^{2}

\frac{\partial}{\partial y} (4) = 0

= 12 x^{3} y^{2} + 0

Simplify

= 12 x^{3} y^{2}

\int_{- 1}^{3} 4 - x^{2} d x

y = \frac{3}{x}, y = 7 x, y = \frac{1}{7} x

f (x) = \frac{( x ^{2} - 6 x )}{x + 1}

\frac{d}{d x} (e^{\frac{x}{a}})

\int x e^{- \frac{1}{2} x} d x

What is (\partial)/(\partial y)(4x^3y^3+4) ?
The answer to (\partial)/(\partial y)(4x^3y^3+4) is 12x^3y^2